Math Detours · Grade 7 · Around the corner · 6

The twelve pentominoes

Five squares joined edge to edge make exactly twelve shapes. Together they cover 60 squares, and fitting them into a rectangle is harder than it looks.

Name ____________________Date ____________

Tonight's idea

A domino is two squares joined along an edge. Join five squares the same way and you have a pentomino. Turning a shape round or flipping it over does not make a new one. With that rule there are exactly twelve, each named after a letter it resembles.

F I L N P T U V W X Y Z
The twelve pentominoes. Each has five squares.

How can anyone be sure none is missing? Search in an orderly way. Sort the shapes by their longest straight row of squares.

That is \(1 + 2 + 8 + 1 = 12\). Twelve shapes of five squares cover \(12 \times 5 = 60\) squares, so the full set might fill a rectangle of area 60.

Watch one: filling a 6 by 10 rectangle

F I L U X P W Y T N V Z
All twelve pieces, each used once, in a 6 by 10 rectangle.

The rectangle has \(6 \times 10 = 60\) squares. Check the letters: all twelve pieces are there, once each, with no gaps and no overlaps.

Finding an arrangement like this by hand can take a long time. A good plan is to place the awkward pieces first. X is the worst. It can never cover a corner square, and its four arms leave notches that other pieces must fill. Save easy pieces such as L and P for the end.

Place, turn and flip the pieces yourself: mathdetours.com/demos/pentomino.html.

Your turn

  1. Every pentomino has area 5. The perimeter is the distance round the outside, counted in sides of a small square. Find the perimeter of I, of X and of P. Eleven of the twelve share one perimeter. Which is the odd one out?
  2. Two copies of the same pentomino can sometimes make a 2 by 5 rectangle. Three of the twelve can do it. Which three? Sketch each rectangle.
  3. (a) List every rectangle with whole-number sides and area 60. (b) Two of them can never be filled by the twelve pentominoes. Which two, and why?
  4. A tetromino is four squares joined edge to edge. Use the longest-row method to find them all. Draw them and say how many there are.

Stretch: no flipping

Suppose the pieces are painted on one side, so you may turn them but not flip them over. Some pentominoes now come in two versions, a left-handed one and a right-handed one. Which ones? How many different pieces are there now?

Answers

  1. I: \(5 + 1 + 5 + 1 = 12\). X: 12. P: 10. P is the odd one out; the other eleven all have perimeter 12. P is the only one containing a 2 by 2 block, so more of its sides are hidden inside the shape.
  2. I, L and P. Two I's lie side by side. Two L's lock together, one turned half way round. Two P's do the same.
  3. (a) 1 by 60, 2 by 30, 3 by 20, 4 by 15, 5 by 12, 6 by 10. (b) 1 by 60 and 2 by 30. The X is three squares wide whichever way you turn it (so are several others), so it cannot fit in a strip only 1 or 2 squares wide. The other four rectangles can all be filled. The 3 by 20 is the hardest: it has only two solutions.
  4. Five. Four in a row: the straight one. Three in a row: the fourth square goes beside an end (an L) or beside the middle (a T). Never more than two in a row: the 2 by 2 square, and the zigzag made of two dominoes, one shifted along by a square.

Stretch. A shape with a mirror line looks the same flipped, so it gains nothing: that is I, T, U, V, W and X. The other six, F, L, N, P, Y and Z, each come in two versions. That makes \(6 + 2 \times 6 = 18\) pieces.

← PreviousNext: Seven kinds of border →